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Sep 12, 2017 at 21:24 comment added Dave Kielpinski I wasn't saying that y = exp(-x/x0) is necessarily the right model function for your problem, just that it looked like a reasonable first guess from your data (which is not available to me). I'm not aware of any general procedure to find the best model function.
Sep 12, 2017 at 9:39 comment added Josh This is useful, but I don't think it get's to the heart of the problem. Wouldn't a model like y = exp(-x/x0) smooth over the interesting variations at different times of the day? Even at the far right of the chart, there are times where there is a zero resource requirement. An exponential relationship wouldn't ever predict zero, even though we want it to.
Sep 8, 2017 at 18:59 review First posts
Sep 8, 2017 at 19:10
Sep 8, 2017 at 18:57 history answered Dave Kielpinski CC BY-SA 3.0