Timeline for Is SVD non-linear while PCA (by eigendecompostion) is linear?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 20, 2018 at 15:58 | comment | added | Outcast | SVD seems to be linear in the sense that it only contains polynomials of degree one (first definition of linearity) but it does not seem to be linear in the sense that SVD(A+B)≠SVD(A)+SVD(B) (second definition of linearity). It would be good if you address this at your post (or I may create a new post regarding in general the two different definitions of linearity). | |
| Nov 20, 2018 at 15:57 | comment | added | Outcast | @KasraManshaei, by the way, let me mention that it is not so unjustifiable why there is a confusion on whether SVD is linear or not (see also here: math.stackexchange.com/questions/1898184/…). If I am not wrong, the whole problem stems from the fact that there are two different definition of linearity (en.wikipedia.org/wiki/Linear_function). | |
| Oct 31, 2018 at 16:08 | comment | added | Martin Thoma | As your answer is the only one and the question title was not so good. I changed it to fit your answer. | |
| Oct 31, 2018 at 11:21 | comment | added | Vaibhav Garg | @MartinThoma The first sentence is an answer to "Is SVD non-linear while PCA (by eigendecompostion) is linear?" | |
| Oct 31, 2018 at 8:47 | comment | added | Martin Thoma | "To the best of my knowledge no." - I have no idea what you reference to. | |
| Oct 31, 2018 at 7:38 | comment | added | Kasra Manshaei | First sentence? | |
| Oct 31, 2018 at 6:24 | comment | added | Martin Thoma | Could you please cite what your first sentence answers? | |
| Oct 27, 2018 at 14:08 | vote | accept | Outcast | ||
| Oct 26, 2018 at 10:13 | history | answered | Kasra Manshaei | CC BY-SA 4.0 |