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Aug 5, 2015 at 17:30 comment added makansij I think I get it @an6u5.
Aug 4, 2015 at 19:57 comment added makansij Have you figured this out? Thanks.
Jul 31, 2015 at 15:54 comment added AN6U5 The distinction between standardizing the cohort and normalizing the individual vectors is confusing when NCC is put in functional form. I'll try to edit my answer over the weekend to hash this out.
Jul 31, 2015 at 9:33 comment added makansij The one part about this that is unclear to me, is - how does this account for the variance in the denominator? It was my understanding that NCC is normalized by the variance of the function. Is that true? I'm not seeing this in your explanation.
Jul 24, 2015 at 22:09 vote accept makansij
Jul 24, 2015 at 22:09 comment added makansij Nice, good explanation.
Jul 22, 2015 at 17:23 history edited AN6U5 CC BY-SA 3.0
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Jul 22, 2015 at 16:30 history edited AN6U5 CC BY-SA 3.0
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Jul 22, 2015 at 11:27 history answered AN6U5 CC BY-SA 3.0