As far as I know, to train learning to rank models, you need to have three things in the dataset:

  • label or relevance
  • group or query id
  • feature vector

For example, the Microsoft Learning to Rank dataset uses this format (label, group id and features).

1 qid:10 1:0.031310 2:0.666667 ...
0 qid:10 1:0.078682 2:0.166667 ...

I am trying out xgBoost that utilizes GBMs to do pairwise ranking. They have an example for a ranking task that uses the C++ program to learn on the Microsoft dataset like above.

However, I am using their Python wrapper and cannot seem to find where I can input the group id (qid above). I can train the model using just the features and relevance scores but I feel like I am missing something.

Here is a sample script.

gbm = XGBRegressor(objective="rank:pairwise")

X =  np.random.normal(0, 1, 1000).reshape(100, 10)
y = np.random.randint(0, 5, 100)

gbm.fit(X, y) ### --- no group id needed???

print gbm.predict(X)

# should be in reverse order of relevance score
print y[gbm.predict_proba(X)[:, 1].argsort()][::-1]
  • $\begingroup$ I also come across this problem, but what kind of set_group should I pass to the function? when I construct a numpy or list I get error like this: d:\build\xgboost\xgboost-git\dmlc-core\include\dmlc\./logging.h:235: [12:03:09] D:\Build\xgboost\xgboost-git\src\c_api\c_api.cc:342: Check failed: (src.info.group_ptr.size()) == (0) slice does not support group structure @amyrit $\endgroup$ – user2404620 Feb 4 '17 at 6:56

According to the XGBoost documentation, XGboost expects:

  • the examples of a same group to be consecutive examples,
  • a list with the size of each group (which you can set with set_group method of DMatrix in Python).
  • $\begingroup$ Thanks, looks like API for model buildling (sklearn.py) is a little incomplete for the Python package. $\endgroup$ – tokestermw Feb 19 '16 at 16:26

set_group is very important to ranking, because only the scores in one group are comparable. You can sort data according to their scores in their own group.

For easy ranking, you can use my xgboostExtension.


protected by Community May 16 at 12:48

Thank you for your interest in this question. Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).

Would you like to answer one of these unanswered questions instead?

Not the answer you're looking for? Browse other questions tagged or ask your own question.