I have two questions on how to produce impulse responses using R

(1) Impulse responses to a negative shock in the independent variable (money supply)

(2) Impulse responses at 2 standard deviations

The code I used to generate the impulse responses to a positive shock at 1 standard deviation is the following:

m1 <- read.csv("m1.csv", header=T)


varm1 <- VAR(m1, p=8, type="cons")

irfm1 <- irf(varm1, impulse="m1", response= c("gdp"), boot = FALSE)



Here is a simple example that should work:

# 1 SD impulse reponse function
# gamma is the number of standard deviations for the irf
irf.rw.e_gamma = irf.rw.e
for(i in 1:n){
    irf.rw.e_gamma$irf$rw[i]   = irf.rw.e_gamma$irf$rw[i]*gamma
    irf.rw.e_gamma$Lower$rw[i] = irf.rw.e_gamma$Lower$rw[i]*gamma
    irf.rw.e_gamma$Upper$rw[i] = irf.rw.e_gamma$Upper$rw[i]*gamma


  • $\begingroup$ in the example above (original question) it is for a positive standard deviation shock. Any idea on how to code a negative 0.25% shock to the policy indicator? $\endgroup$
    – Rollo99
    Feb 28 '20 at 10:27
  • 1
    $\begingroup$ I tweaked the code so that it could make an IRF for an arbitrary size and sign inpulse. The object irf.rw.e holds the basic 1 std dev positive irf, and irf.rw.e_gamma holds the irf for the a shock of gamma standard deviations. So if you want it to be -0.25, set gamma=-0.25. I also patched an issue where the confidence intervals may not be correct. This matches the confidence intervals to size of the shock (bigger shocks, bigger bounds). $\endgroup$
    – BKay
    Feb 28 '20 at 11:44
  • $\begingroup$ thanks so much! Super super helpful, can't give you more points on the solution as I already gave you all on the previous one. Thanks a lot again $\endgroup$
    – Rollo99
    Feb 28 '20 at 11:45
  • $\begingroup$ do you know how to do the same but using externalinstrument? I can post a question. I have already posted one on stackoverflow here $\endgroup$
    – Rollo99
    Mar 12 '20 at 12:33

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