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While tuning the SVM classification model in Matlab, I came across the rng function in matlab in which seed (stabilizes the random shuffling of the data in the algorithm) is changed. When the function called is rng(1) then I am getting one accuracy value (99%). When it is changed to rng(2) then I am getting another value (57%). So there is a huge change in accuracy as visible. What does this mean? Am I training it wrong?

The train and test set correct rate (in %) that I am getting with different runs without changing rng are(train,test)
(96, 82.8)
(94.6, 95.3)
(96, 85.9)
(96, 90)
(95, 95)

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    $\begingroup$ What are the testing errors of both? Nothing can be said by just looking at the training errors. Maybe rng(1) is better than rng(2) or maybe it is overfitting. $\endgroup$
    – Dawny33
    Commented Aug 9, 2016 at 5:48
  • $\begingroup$ @Dawny33 So does this mean that there is overfitting? A good model should have the same accuracy for any rng right? $\endgroup$
    – girl101
    Commented Aug 9, 2016 at 5:52

1 Answer 1

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The training errors in this dataset has a huge difference (99% vs 57%). So, maybe the one with the rng(1) split has overfitted your dataset.

So there is a huge change in accuracy as visible. What does this mean? Am I training it wrong?

The huge change might be due to overfitting. (Also, judge the model through validation curves, and then fit a model which balances the bias-variance plot.)

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  • $\begingroup$ made a small change in the question. Let me know whether still there is over-fitting or not $\endgroup$
    – girl101
    Commented Aug 9, 2016 at 7:15
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    $\begingroup$ @Rishika No, I don't think there's any overfitting there. But, that's without changing the rng value, right? $\endgroup$
    – Dawny33
    Commented Aug 9, 2016 at 7:17
  • $\begingroup$ yes. This is without changing rng $\endgroup$
    – girl101
    Commented Aug 9, 2016 at 7:22
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    $\begingroup$ @Rishika The model looks good to me, then :) $\endgroup$
    – Dawny33
    Commented Aug 9, 2016 at 7:25

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