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I have a multiclass SVM classifier with labels 'A', 'B', 'C', 'D'.

This is the code I'm running:

>>>print clf.predict([predict_this])
['A']
>>>print clf.decision_function([predict_this])
[[ 185.23220833   43.62763596  180.83305074  -93.58628288   62.51448055  173.43335293]]

How can I use the output of decision function to predict the class (A/B/C/D) with the highest probability and if possible, it's value? I have visited https://stackoverflow.com/a/20114601/7760998 but it is for binary classifiers and could not find a good resource which explains the output of decision_function for multiclass classifiers with shape ovo (one-vs-one).

Edit:

The above example is for class 'A'. For another input the classifier predicted 'C' and gave the following result in decision_function

[[ 96.42193513 -11.13296606 111.47424538 -88.5356536 44.29272494 141.0069203 ]]

For another different input which the classifier predicted as 'C' gave the following result from decision_function,

[[ 290.54180354 -133.93467605  116.37068951 -392.32251314 -130.84421412   284.87653043]]

Had it been ovr (one-vs-rest), it would become easier by selecting the one with higher value, but in ovo (one-vs-one) there are (n * (n - 1)) / 2 values in the resulting list.

How to deduce which class would be selected based on the decision function?

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Your link has sufficient resources, so let's go through:

When you call decision_function(), you get the output from each of the pairwise classifiers (n*(n-1)/2 numbers total). See pages 127 and 128 of "Support Vector Machines for Pattern Classification".

Click on the "page 127 and 128" link (not shown here, but in the Stackoverflow answer). You should see:

enter image description here

  • Python's SVM implementation uses one-vs-one. That's exactly what the book is talking about.
  • For each pairwise comparison, we measure the decision function
  • The decision function is the just the regular binary SVM decision boundary

What does that to do with your question?

  • clf.decision_function() will give you the $D$ for each pairwise comparison
  • The class with the most votes win

For instance,

[[ 96.42193513 -11.13296606 111.47424538 -88.5356536 44.29272494 141.0069203 ]]

is comparing:

[AB, AC, AD, BC, BD, CD]

We label each of them by the sign. We get:

[A, C, A, C, B, C]

For instance, 96.42193513 is positive and thus A is the label for AB.

Now we have three C, C would be your prediction. If you repeat my procedure for the other two examples, you will get Python's prediction. Try it!

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  • $\begingroup$ How did you deduce that class 'A' has the largest value? For a class 'C' value I got [[ 96.42193513 -11.13296606 111.47424538 -88.5356536 44.29272494 141.0069203 ]] $\endgroup$ – Samkit Jain Apr 15 '17 at 12:32
  • $\begingroup$ @SamkitJain Edit your question for your new details. Share as much as you think you should. Don't let us guess. $\endgroup$ – SmallChess Apr 15 '17 at 12:33
  • $\begingroup$ I have edited the question with more examples $\endgroup$ – Samkit Jain Apr 15 '17 at 12:50
  • $\begingroup$ @SamkitJain EDITED $\endgroup$ – SmallChess Apr 15 '17 at 13:05
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You can use CallibratedClassifierCV.

from sklearn.calibration import CalibratedClassifierCV

model_svc = LinearSVC()
model = CalibratedClassifierCV(model_svc) 

model.fit(X_train, y_train)
pred_class = model.predict(y_test)
probability = model.predict_proba(predict_vec)
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