2
$\begingroup$

Let's say we want to predict the probability of rain. So just the binary case: rain or no rain.

In many cases it makes sense to have this in the [5%, 95%] interval. And for many applications this will be enough. And it is actually desired to make the classifier not too confident. Hence cross entropy (CE) is chosen:

$$H_{y'} (y) := - \sum_{i} y_{i}' \log (y_i)$$

But cross entropy practically makes it very hard for the classifier to learn to predict 0. Is there another objective function that does not behave that extreme around 0?

Why it matters

There might be cases where it is possible to give the prediction 0% (or at least something much closer to 0 like $10^{-6}$). Like in a desert. And there might be applications where one needs this (close to) zero predictions. For example, when you want to predict the probability that something happens at least once. If the classifier always predicts at least a 1% chance, then having rain at least once in 15 days is

$$1 - (1-0.05)^{15} \approx 54\%$$

but if the classifier can practically output 0.1% as well, then this is only

$$1 - (1-0.001)^{15} \approx 1.5\%$$

I could also imagine this to be important for medical tests or for videos.

$\endgroup$
  • $\begingroup$ Substitute $1-(1-y_i)^k$ for $y_i$ in your cross entropy loss function? For small values $1-(1-y_i)^k \approx ~k y_i$ anyway, so the result may not be wildly different if you guess well. $\endgroup$ – Emre Apr 16 '18 at 18:59
  • 1
    $\begingroup$ Side note, your computations assume a rain event is independent from one day to the next, which is definitely not the case. I don’t think that’s crucial to your actual question though. $\endgroup$ – kbrose Apr 16 '18 at 23:34

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.