From my understanding you have dataframe containing a list of Buyer ID's, the product they bought and how many of it they bought. You want to find out what percentage of the total of each product bought each customer was responsible.
For instance if buyer 1 bought all of A then they would 100% and if buyer 2 bought half of all B then they would be 50%.
Each buyer only buys one type of product at a time.
I generated a dataset to replicate this as so:
options = 'ABCDEF'
product = []
count = []
buyer = []
for i in range(0,100):
product.append(test[np.random.randint(0,5)])
count.append(np.random.randint(0,10))
buyer.append(i)
df = pd.DataFrame(data = [buyer, product, count]).transpose()
df.columns = ['buyer','product','count']
print(df.head())
>>> buyer product count
0 0 B 4
1 1 B 6
2 2 A 2
3 3 D 2
4 4 D 5
In order to calculate each customers percentage you will need the total count of each product bought
totals = {'A' : 0,
'B' : 0,
'C' : 0,
'D' : 0,
'E' : 0,
'F' : 0}
for i in range(0, len(df)):
currentProduct = df.iloc[i,1]
totals[currentProduct] = totals[currentProduct] + 1
Now all you need to do is calculate count/total for each product and save to a new column in the dataframe.
for i in range(0, len(df)): # Iterate over every row in
# new column | count bought | total bought by all
df.iloc[i,3] = df['count'][i]/totals[df['product'][i]]
print(df.head())
>>> buyer product count contribution
0 0 B 4 0.210526
1 1 B 6 0.315789
2 2 A 2 0.080000
3 3 D 2 0.111111
4 4 D 5 0.277778
print(totals)
>>> {'A': 25, 'B': 19, 'C': 15, 'D': 18, 'E': 23, 'F': 0}
I know it's not the same method that you where using but it should still work, if you want please post a sample of your code so that we can look bugs, alternatively just tick this answer and change the title to represent the question that was answered.
If i misunderstood anything just say so