# Generating a sequence based on value in another column in Python

I have the following data frame: I would like to add a column with value equal to 1 if flag is 0 and incrementally add 1 in the following rows until the next 0 is encountered (as given in the example below). I have been able to generate the sequence, but the code is extremely slow, so is there a faster way to generate the sequence?

• Can you show us your attempt? – ukemi Feb 24 '19 at 9:25

## 1 Answer

I don't know how you have tested it the first time, here is my logic. It supposes the first element in flag is 0!

df = pd.DataFrame({'memberid': *11,
'flag': [0,0,1,1,0,1,0,0,0,1,1],
})
df['seq'] = ""
for i in range(0, len(df)):
df.loc[i, 'seq'] = 1 if df.loc[i, 'flag'] == 0 else  df.loc[i - 1, 'seq'] + 1
print(df)


Another solution using lambda:

df = pd.DataFrame({'memberid':  * 11,
'flag': [0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 1]
})

def f(flag):
global previous_seq
previous_seq = 1 if flag == 0 else previous_seq + 1
return previous_seq

previous_seq = 0
df['seq'] = df[['flag']].apply(lambda x: f(*x), axis=1)
print(df)


I am not sure if it is faster than the first solution....