I have dataframe and let's say inside of it is a column_A. This column_A has 3 strings as values, call them 'new_records', 'deletions', 'changes' that repeat across the dataframe multiple times in that order always with multiple rows in between. I want to delete all rows from the beginning of deletions to the end of changes, i.e. I want to leave only new_records in the dataframe. The dataframe looks like this:

column_A         column_B     column_C ....
NEW_RECORDS        val1         val2
string1_new        val3         val4 
string2_new        val5         val6 
  NaN              val9         val10
  NaN              val11        val12 
DELETIONS          val7         val8
string1_del         ...           ...
   NaN              ...           ...
string2_del         ...           ...
CHANGES             ...           ...
 str1_ch            ... 
 str200_new        ...
 str300_new           ...
 str290_del        ...
   ...           ...

I want to have at the end only chunks of rows between new_records and deletions values, without rows that belong to the deletions group and changes group. How can I do that?


There are many rows after the 'new_records' and before the start of 'deletions' group and there are many rows after the start of deletions group and beginning of the 'changes' group. I need to extract only rows that belong to the new_records group. So all rows after the value 'new_records' and before the value of 'deletions' across all dataframe.

  • 1
    $\begingroup$ The function you are looking for is drop $\endgroup$ Apr 17, 2019 at 15:39
  • $\begingroup$ Drop what? How? Can you be more specific? $\endgroup$
    – BlueIvy
    Apr 17, 2019 at 15:40
  • $\begingroup$ This link can help you: pandas.pydata.org/pandas-docs/stable/reference/api/… $\endgroup$ Apr 17, 2019 at 15:40
  • $\begingroup$ I am still not sure how to drop rows between values that repeat multiple times across dataframe. $\endgroup$
    – BlueIvy
    Apr 17, 2019 at 15:45
  • $\begingroup$ First fill the values of the empty column_A cells and then drop the "deletions" and "changes" rows $\endgroup$
    – pcko1
    Apr 18, 2019 at 13:59

1 Answer 1


You can achieve this by forward filling the blank values, and then selecting only those with new_records:


df = df[df['column_A'] == 'new_records']

Depending on the actual values in your data frame, you may need to first replace what appear to be empty/space strings with NaN's:

df['column_A'] = df['column_A'].replace(r'^\s*$', np.nan, regex=True)
  • $\begingroup$ Unfortunately, this won't work because there are other strings that belong to different groups, not only NaN values. I updated how the dataframe looks like. $\endgroup$
    – BlueIvy
    Apr 23, 2019 at 10:13
  • 1
    $\begingroup$ @user68225 idea: replace all 'column_A' values not equal to 'NEW_RECORDS', 'DELETIONS', 'CHANGES' with NaN then forward fill etc $\endgroup$
    – iacob
    Apr 23, 2019 at 10:20
  • $\begingroup$ That worked! Thank you! $\endgroup$
    – BlueIvy
    Apr 23, 2019 at 10:42

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