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I'm working on a sample project and one of the features is the job description of a person (categorical, for example: blue-collar, retired, unknown, unemployed, student, etc.). Since in the future more job descriptions could be used, I don't think one hot encoding it's the best approach. How would you encode it without using one hot encoding??

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    $\begingroup$ What's the goal of the project? If it's a sample project and you already have a dataset in hand, why worry about additional values in the future? $\endgroup$
    – zachdj
    Mar 23 '20 at 16:49
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I would first start by using something like scikit-learn LabelEncoder. Examples are in the documentation.

EDITED : With this option, you convert every string to a integer starting from 1.

You can also think about trying to convert the strings into hash values.

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    $\begingroup$ LabelEncoder outputs values between 1 and k, not 0 and 1. The problem with this is that by giving some class a greater value than other class, the model might be more biased towards the bigger value, which is what I'm trying to avoid. $\endgroup$
    – shulito
    Apr 29 '19 at 13:29
  • $\begingroup$ The problem with LabelEncoder pointed by @shulito is true. Apart from that, an algorithm could learn that the sum of two categories are the same as a third category, which would make absolutely no sense. I always take LabelEncoding with great care! It looks like a simple and efficient approach, but it may be dangerous! $\endgroup$
    – 89f3a1c
    Oct 23 '19 at 22:38
  • $\begingroup$ Yes my bad, after a few months, I don't know why I wrote 0 to 1. I will edit the answer. You are right, that you might have a biased model but I did have nice surprises in the past trying it anyway. $\endgroup$
    – eetuko
    Oct 25 '19 at 13:46
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1) Try with LabelEncoding(fast way, but not best way)

#Assuming that you have data in Pandas dataframe

def encode_to_num_df(df):
        from sklearn.preprocessing import LabelEncoder
        df = df.apply(LabelEncoder().fit_transform)
        return df

2) Custom encoding each label - best way, but the hardest. Detailed explanation there. Thanks to @Djib2011

my_mapping = {'bad': 1, 'worse': 2, 'worst': 3}


df['feature'] = df['feature'].map(my_mapping)

Source:

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