Assume I have a dataset with three inputs:

   x1   x2  x3  
0  a    b   c
1  d    e   f
2  g    h   i
3  j    k   l
4  m    n   o
5  p    q   r
6  s    t   u 

0,1,2,3 are times, x1, x2, x3 are inputs that are measured. So here x1 inputs are measured at every one hour. x2 and x3 will be measured at different time. What I need to do , I want write that what ever the measured in x1, x2, x3 it will add and subtract the values are equal to the x1 input next time value So here what I want to do is:

    x1   x2   x3   y
 0  a    b    c   a+b-c==d
 1  d    e    f   d+e+f==g
 2  g    h    i   g+h-i==j
 3  j    k    l   j+k-l==m
 4  m    n    o   m+n-o==p
 5  p    q    r   p+q-r==s
 6  s    t    u   s+t-u==v

I tried shift method and it didn't work for me what I want exactly. I tried another method and it worked, but didn't came as I want. Here I upload the code.

Code :
 data = pd.read_csv('data6.csv')
 while j < len(data):
   j=data['x1'][i] - data['x2'][i] + data['x3'][i] 

This is works , but it is just showing only one data


In my csv file this is second input value of x1 input. I want to write this code contonously happened and read the value as I shown above. Can anyone help me to solve this problem?

My csv file


1 Answer 1


So are you evaluating the equality of a+b-c and d for each sample? Meaning, you aim to save the boolean value? If so:

import pandas as pd
#a sample dictionary
data = {'x1':[1,0,4,5,8,1], 
df = pd.DataFrame(data) #converting the dictionary to dataframe
df['y'] = 0 #initializing the y column with 0, also you can initialize with FALSE boolean value
for i in range(len(df)-1): #iterating between all the rows of dataframe
    df['y'].iloc[i] = df['x1'].iloc[i] + df['x2'].iloc[i] - df['x3'].iloc[i] == df['x1'].iloc[i+1] 

Note: for the last row, since the content of column y should be calculated based on the next row, the value cannot be calculated, that is why we have set (len(df)-1).


   x1  x2  x3      y
0   1   3   4   True
1   0   4   5  False
2   4   5   1  False
3   5   6  -2  False
4   8   8   4  False
5   1   9   5      0

The problem with your code: First, you are not considering that subsequent row to calculate the accuracy of the expression $a+b-c ==d$ Second, if that print(j) is outside the loop, is it? then you are looping in the rows of data frame while j is less than data frame's length, So when the flow is out of this while, a single value j would be returned.

  • $\begingroup$ Thank you for the fast reply. I used your code , and it shows the same as you shown below. But I want to show the values not true or false, If I want to display value then how to chsnge the code? $\endgroup$
    – bala
    Jul 14, 2019 at 4:17
  • $\begingroup$ yes j is in out loop, what about write in while loop ? $\endgroup$
    – bala
    Jul 14, 2019 at 4:22
  • $\begingroup$ Here what I want is by adding or subtracting what ever the value is coming it will be equal to the x1 column next value (!=) $\endgroup$
    – bala
    Jul 14, 2019 at 4:24
  • 1
    $\begingroup$ If so you just need to write: python df['y'].iloc[i] = df['x1'].iloc[i+1] in the last line of the code. $\endgroup$ Jul 15, 2019 at 3:09
  • 1
    $\begingroup$ Wooww it worked . Thank you. $\endgroup$
    – bala
    Jul 15, 2019 at 4:29

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