# how to perform Step calcuations in R

I have a rate-step plan for consumption with which I'm trying to total up costs. I have a rate plant that looks like this:

First 20 Kwh is Free;
Second 5 Kwh is $.1 Next 100 Kwh is$.053
Next 875 Kwh is $.042 Over 1000Kwh is$.039


Can someone provide a worked example for me, e.g., with $\text{consumtpion}=625$? If possible, with R code for calculating the total cost.

For my own approach, I was thinking of using a loop, but if it's a lot of accounts the loop will take too long. Can anyone think of a vector-based approach for calculating the result?

• Yes a worked example would be useful, from you, to tell us how much a consumption of 625 would cost. You could do this very easily. – Spacedman Jul 25 '15 at 7:47
• Did any of the existing answers solved your problem? – Dawny33 Nov 23 '15 at 9:59

Try a simple equation like this: \begin{eqnarray} &&\max(x-20,0)*0.1 + \max(0,x-25)*(-.047) + \\ &&\max(0, x-125)*(-.011) + \max(0,x-1000)*(-.003) \end{eqnarray}

This should take the usage $(x)$ and walk it through steps, initially charging 0.1 for each Kwh over 20: $\max(x-20,0)*0.1$

Then, if $x$ is above 20, it takes away 0.047 (0.1-0.053) for every Kwh between 20 and 25: $\max(0, x-25)*(-0.047)$

Then, if $x$ is above 125, it takes away 0.011 (0.053-0.042) for every Kwh between 25 and 125: $\max(0, x-125)*(-0.011)$

• I'm sorry Duncan, I thought I tagged it already. Thanks much. This did work for me. – arcee123 Nov 23 '15 at 15:22
• No problem! I'm glad that it works. – Duncan Nov 23 '15 at 21:25

Here's a naïve implementation of your pseudocode in R:

calculate_cost <- function(kwh){
if(kwh < 20){
return(0)
}else{
kwh <- kwh - 20
if(kwh <= 5){
return(kwh * 0.1)
}else{
final_cost <- kwh * 0.1
kwh <- kwh - 5
if(kwh <= 100){
return(final_cost + (kwh * 0.053))
}else{
final_cost <- final_cost + (kwh * 0.053)
kwh <- kwh - 100
if(kwh <= 875){
return(final_cost + (kwh * 0.042))
}else{
final_cost <- final_cost + (kwh * 0.042)
kwh <- kwh - 875
return(final_cost + (kwh * 0.039))
}
}
}
}
}


Then,

> calculate_cost(kwh=625)
 113.3