2
$\begingroup$

I would like to perform a multiclass-multioutput classification task, on vectorized textual data. I started by using a random forest classifier in a multioutput startegy:

    forest = RandomForestClassifier(random_state=1)
    multi_target_forest = MultiOutputClassifier(forest, n_jobs=-1)
    multi_target_forest.fit(X_train, y_train)
    y_pred_test = multi_target_forest.predict(X_test)

When looking on the feature importance for the individual estimators (multi_target_forest.estimators_ ) I've noticed that some features in my dataset are very relevant and useful for some tasks, but are disrupting for another class. Example:

Task 1: classify documents for Date (q1, q2, q3, q4) Task 2: classify document for Version (preliminary, final, amendment)

For task 1, features related to dates, such as 'April', are very useful. However, for the second task, the feature 'April' gets a high importance but is a consequence of overfitting to a small dataset. Knowing this I would like to actively remove such features.

Is there a way to control which features are used for every task?

I could just explicitly train separate classifiers for every task, but is that equivalent to multioutput-multiclass? or is there some joined probability calculation going on, that I'll be missing?

Thank you!

$\endgroup$

1 Answer 1

0
$\begingroup$

I don't think its possible.

First, let's see what's the difference in explicitly modeling separate trees for different tasks versus modeling them in joint manner.

Lets suppose we have 2 task with each n classes. In the later case, to be able to jointly model the correlations, one must create new classes which is a subset of all the permutations available from nC2 combination of the classes from the 2 tasks. Now, if it is true that one feature (say feature A) is beneficial for task 1 but not for task 2, then how would one decide whether to use the feature A while figuring out the final classes in both the task? Task 1 wants the feature but Task 2 doesn't, so this creates a deadlock which would prevent us from putting a bias in the tree model to not use feature A for the classification!

So, if you are certainly sure that a particular feature is not beneficial for a particular task the then the simpler and more effective way would be to model them separately as you mentioned.

$\endgroup$
3
  • $\begingroup$ Makes sense. Thank you! $\endgroup$
    – R Sorek
    Commented Mar 8, 2020 at 6:21
  • $\begingroup$ Thanks for accepting my answer and welcome to stack exchange! Can you also 'upvote' my answer? $\endgroup$ Commented Mar 9, 2020 at 6:07
  • $\begingroup$ sure, but this will be displayed only once I have enough reputation points. $\endgroup$
    – R Sorek
    Commented Mar 11, 2020 at 6:11

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.