A bidirectional RNN consists of two RNNs, one for the forward and another for the backward sequential directions, which outcome is concatenated at each time step. Would this configuration restrict the model to always use a fixed sequence length? Or would it still work as the unidirectional RNN, which can be applied to any sequence length?

This question was raised because the bidirectional architecture merges the output of both forward and backward RNNs at each time step. Thus, if the sequence length was 4, the outputs of both forward and backward RNNs would merge this way: 1th forward with 4th backward, 2nd forward with 3rd backward,... 4th forward with 1st backward. However, if a different sequence length was used this merge order would be modified:

Let's say the network was trained with sequence length 4, but at test time a sequence length of 5 was used. Merge would be: 1th forward with 5th backward, 2nd forward with 4th backward... 5th forward with 1th backward. Would this shift in merge order negatively affect the bidirectional RNN performance?


The short answer is no, a bidirectional architecture will still take in a variable sequence length. To understand why, you should understand how padding works.

For example, let's say you are implementing a bidirectional LSTM-RNN in tensorflow on variable length time series data for multiple subjects. The input is a 3D array with shape: [n_subjects, [n_features, [n_timesteps...] ...] ...] so to ensure that the array has consistent dimensions, you pad the other subject's features up to the length of the subject with features measured for the longest period of time.

Let's say subject 1 has one feature with values = [22,20,19,21,33,22,44,21,19,26,27] measured at times = [0,1,2,3,4,5,6,7,8,9,10]. subject 2 has one feature with values = [21,12,22,30,13,42,20] measured at times = [0,1,2,3,4,5,6]. You would pad features for Subject 2 by extending the array so that the padded_values = [21,12,22,30,13,42,20,0,0,0,0] at times = [0,1,2,3,4,5,6,7,8,9,10], then do the same thing for every subsequent subject.

This means the number of timesteps for each subject can be variable, and the merge you refer to occurs with the dimension for that particular subject.

Below is an example of a bidirectional LSTM-RNN architecture for a model that predicts sleep stages for different subjects using biometric features measured over variable lengths of time.

enter image description here

  • $\begingroup$ Does this mean we always need a padding in bidirectional RNN if we want to use variable sequence length? $\endgroup$ – DiMorten - Jorge Chamorro Jun 11 '20 at 16:58
  • $\begingroup$ Yes you need padding for any RNN with variable sequence length, at least when you feed the 3D data array into a model built in Keras or Tensorflow. $\endgroup$ – Derek O Jun 11 '20 at 19:06

Yes, there is a way with TF 2.0, which is to use Ragged Tensors as below:

# Task: predict whether each sentence is a question or not.
sentences = tf.constant(
    ['What makes you think she is a witch?',
     'She turned me into a newt.',
     'A newt?',
     'Well, I got better.'])
is_question = tf.constant([True, False, True, False])

# Preprocess the input strings.
hash_buckets = 1000
words = tf.strings.split(sentences, ' ')
hashed_words = tf.strings.to_hash_bucket_fast(words, hash_buckets)

# Build the Keras model.
keras_model = tf.keras.Sequential([
    tf.keras.layers.Input(shape=[None], dtype=tf.int64, ragged=True),
    tf.keras.layers.Embedding(hash_buckets, 16),
    tf.keras.layers.LSTM(32, use_bias=False),

keras_model.compile(loss='binary_crossentropy', optimizer='rmsprop')
keras_model.fit(hashed_words, is_question, epochs=5)

Source: https://www.tensorflow.org/guide/ragged_tensor

New contributor
DigitalFox is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.