There is a package named segmented in R. Is there a similar package in python?
-
$\begingroup$ Is there anything specific that you need? For known break points, this can just be modeled by an interaction with a indicator function (0 before, 1 after the break) or a linear spline. The first approach has a jump, the second approach results in a connected piecewise regression line. $\endgroup$– JosefOct 2, 2015 at 4:28
-
$\begingroup$ LINEAR-TREE (sklearn wrapper): github.com/cerlymarco/linear-tree $\endgroup$– Marco CerlianiMay 19, 2021 at 15:13
3 Answers
No, currently there isn't a package in Python that does segmented linear regression as thoroughly as those in R (e.g. R packages listed in this blog post). Alternatively, you can use a Bayesian Markov Chain Monte Carlo algorithm in Python to create your segmented model.
Segmented linear regression, as implemented by all the R packages in the above link, doesn't permit extra parameter constraints (i.e. priors), and because these packages take a frequentist approach, the resulting model doesn't give you probability distributions for the model parameters (i.e. breakpoints, slopes, etc). Defining a segmented model in statsmodels, which is frequentist, is even more restrictive because the model requires a fixed x-coordinate breakpoint.
You can design a segmented model in Python using the Bayesian Markov Chain Monte Carlo algorithm emcee. Jake Vanderplas wrote a useful blog post and paper for how to implement emcee with comparisons to PyMC and PyStan.
Example:
- Segmented model with data:
- Probability distributions of fit parameters:
This is an implementation of my own.
import numpy as np
import matplotlib.pylab as plt
from sklearn.tree import DecisionTreeRegressor
from sklearn.linear_model import LinearRegression
# parameters for setup
n_data = 20
# segmented linear regression parameters
n_seg = 3
np.random.seed(0)
fig, (ax0, ax1) = plt.subplots(1, 2)
# example 1
#xs = np.sort(np.random.rand(n_data))
#ys = np.random.rand(n_data) * .3 + np.tanh(5* (xs -.5))
# example 2
xs = np.linspace(-1, 1, 20)
ys = np.random.rand(n_data) * .3 + np.tanh(3*xs)
dys = np.gradient(ys, xs)
rgr = DecisionTreeRegressor(max_leaf_nodes=n_seg)
rgr.fit(xs.reshape(-1, 1), dys.reshape(-1, 1))
dys_dt = rgr.predict(xs.reshape(-1, 1)).flatten()
ys_sl = np.ones(len(xs)) * np.nan
for y in np.unique(dys_dt):
msk = dys_dt == y
lin_reg = LinearRegression()
lin_reg.fit(xs[msk].reshape(-1, 1), ys[msk].reshape(-1, 1))
ys_sl[msk] = lin_reg.predict(xs[msk].reshape(-1, 1)).flatten()
ax0.plot([xs[msk][0], xs[msk][-1]],
[ys_sl[msk][0], ys_sl[msk][-1]],
color='r', zorder=1)
ax0.set_title('values')
ax0.scatter(xs, ys, label='data')
ax0.scatter(xs, ys_sl, s=3**2, label='seg lin reg', color='g', zorder=5)
ax0.legend()
ax1.set_title('slope')
ax1.scatter(xs, dys, label='data')
ax1.scatter(xs, dys_dt, label='DecisionTree', s=2**2)
ax1.legend()
plt.show()
Yes, there is now a Python package called piecewise-regression
that implements similar tools to the segmented R package, using the same algorithm.
You can get it from pip
pip install piecewise-regression
There are full docs, a github repo, and an accompanying paper.
Here's an example fit:
It's very easy-to-use, code examples here.
Full disclosure: I wrote the package.