I have a dataset like the one below. I want to remove all characters after the character ©. How can I do that in R?

data_clean_phrase <- c("Copyright © The Society of Geomagnetism and Earth", 
"© 2013 Chinese National Committee ")

data_clean_df <- as.data.frame(data_clean_phrase)
  • $\begingroup$ Is it after a specific character, or after a specific index? $\endgroup$ – Dawny33 Nov 19 '15 at 13:39
  • $\begingroup$ After a specific character: © $\endgroup$ – Hamideh Nov 19 '15 at 16:24
  • $\begingroup$ Then, seems like the existing answer solved your question :) $\endgroup$ – Dawny33 Nov 19 '15 at 16:26

For instance:

 rs<-c("copyright @ The Society of mo","I want you to meet me @ the coffeshop")
 [1] "copyright "             "I want you to meet me "

Or, if you want to keep the @ character:

 [1] "copyright @"             "I want you to meet me @"

EDIT: If what you want is to remove everything from the last @ on you just have to follow this previous example with the appropriate regex. Example:

rs<-c("copyright @ The Society of mo located @ my house","I want you to meet me @ the coffeshop")
[1] "copyright @ The Society of mo located " "I want you to meet me "

Given the matching we are looking for, both sub and gsub will give you the same answer.

| improve this answer | |
  • $\begingroup$ Thank you. and What if I want to do it for the last © in the text. Consider this: c(" © aaa © bbb") --> c( "© aaa") $\endgroup$ – Hamideh Nov 19 '15 at 15:36
  • $\begingroup$ @HamidehIraj You can make use of regexes for executing that. $\endgroup$ – Dawny33 Nov 19 '15 at 16:26
  • 1
    $\begingroup$ You are welcome. Once you get use to regex you'll see that it is as easy to remove from the last @ char. I've edited my answer to include this case as well. $\endgroup$ – MASL Nov 19 '15 at 17:27

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