I am working on a data, for preding output, I used SVR by bellow code:

from sklearn.svm import SVR
regressor = SVR(kernel = 'linear')

from sklearn.metrics import r2_score
pred = regressor.predict(testX)

The answer is : [0.58439621 0.58439621 0.58439621 ... 0.81262134 0.81262134 0.81262134]. I'm trying to inverse the scaling to real amount.

I search it in StackOverflow and reach this: https://stackoverflow.com/questions/49330195/how-to-use-inverse-transform-in-minmaxscaler-for-a-column-in-a-matrix, I implement every 2 answers in my code, but I get error yet. Can anyone help me with this?

I write this from above source:

import sklearn
from sklearn.preprocessing import MinMaxScaler

but, I got same error as:

Blockquote Expected 2D array, got 1D array instead: array=[0.58439621 0.58439621 0.58439621 ... 0.81262134 0.81262134 0.81262134]. Reshape your data either using array.reshape(-1, 1) if your data has a single feature or array.reshape(1, -1) if it contains a single sample. Blockquote


From my understanding you are working on a regression task in which you have applied MainMaxScaler to your target variable y prior modeling.

If so you have two options:

  1. As the error message suggests, you can reshape the output with array.reshape(-1, 1)

  2. Scikit learn has implemented a class to work with transformations on target:

So just try

from sklearn.svm import SVR
from sklearn.compose import TransformedTargetRegressor
from sklearn.metrics import r2_score
from sklearn.preprocessing import MinMaxScaler

regressor = SVR(kernel = 'linear')

model = TransformedTargetRegressor(regressor= regressor,
                                        transformer = MinMaxScaler()

pred = model.predict(testX)

Every time you make a model.predict(X) it will apply an inverse transformation so that your predictions are in the same scale as prior MinMaxScaler


Working example of transformation without using Scikit-learn

# array example is between 0 and 1
array = np.array([0.58439621, 0.81262134, 0.231262134, 0.191])
#scaled from 100 to 250
minimo = 100
maximo = 250
array * minimo + (maximo - minimo)


array([208.439621 , 231.262134 , 173.1262134, 169.1])
  • $\begingroup$ Thanks. That was so helpful. I have a question, you know by normalization the pred scale is between 0 and 1. now, how could I transfer this scale to the data scale (real value). for example:[0.58439621 0.58439621 0.58439621 ... 0.81262134 0.81262134 0.81262134], the pred answer transfer to :[250 100 50 60 .....]. $\endgroup$ – ramin Feb 18 at 8:20
  • $\begingroup$ thanks@Julio Jesus, you help me. $\endgroup$ – ramin Feb 18 at 18:53

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