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I found the answer in the comments section of their blog: Earnings listed on the public-score leaderboard are potential winnings. Actual winnings are determined by the private-score leaderboard. At the time of withdrawal and when new datasets are released, your actual winnings will be revealed to you.

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It's a technically rigorous course. Recommend? It depends on what your goal is. Definitely, if your goal is to compete on Kaggle. Not really, if you want to improve practical ML. Remember, Kaggle is kind of Formula 1. The fastest car wins. But in the real world, you don't always need a Formula 1 car. Sometimes you need an SUV, sometimes you need a van, ...

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As oW_ mentioned, this can be done with the Elo rating system. More specifically, given a record of wins and losses for some player pool, you can fit ratings for each player such the expected result of player $A$ rated $r_A$ vs player $B$ rated $r_B$ is given by: $$E_{A\ vs\ B} = \frac{1}{1 + 10^{(r_B-r_A)/400}}$$ When the only possible outcomes are win ...

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I've looked at the approach and I'd select K by trying a range, i.e. 5k, 10k, 15k etc and then exploring the range in which the best result falls, say the best is 15k then I might do 13, 14, 15, 16, 17 and so on. So far I've not found any pre-processing to be effective. Answering the comment: I've tried using LogisticRegression, SVM, Neural Networks, ...

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If I understand the problem correctly, you want to fill all missing values in the Fare column by the median value of the Fare column where Pclass=3. This can be achieved by putting the extra row filter test['Pclass']=3 on median of the fare column, see below. test['Fare'] = test['Fare'].fillna(test.loc[test['Pclass']=3,'Fare'].median())

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This is a generic question that may need more than just cash prize. 1) Organizational Reputation 2) Dataset Size 3) Defining Problem statements with Domain knowledge 4) Time period 5) Computation required for the contest. 6) How curated/clean is the dataset and much more. If the problem statement is huge and the reward is in single digits, its not worth ...

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