Can anyone help me about cost function in linear regression. As from the below plot we have actual values and predicted values and I assumed the answer as zero but it actually is 14/6?
Can anyone help out please?
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$h_\theta$ implies that you're trying to model the relation between $h$ and $x$ with an straight line coming from the origin $(0,0)$. The parementer $\theta_1$ is the slope of this line.
Evaluating $J(\theta_1=0) = J(0)$, implies that $h_\theta(x_i)=0$ whatever the value of $x_i$ is. Since $m=3$, and the labels are $y_1=1, y_2=2, y_3=3$
$J(0) = \frac{1}{6}[(0 -1)^2 + (0 - 2)^2 + (0-3)^2] = \frac{14}{6}$
The value of $\theta_1$ for which $J(\theta_1) = 0$ is obviously 1
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y1=1ory1=0? In the equation you did(0-1)^2? $\endgroup$ Commented Dec 13, 2018 at 6:29 -