2
$\begingroup$

I am fitting my data to a multivariate linear regression $Y = BX + \Xi$, where the response is bivariate $Y\in R^{n\times 2}$, and the predictor is uni-variate but elevated to the projective plane to account for the intercept $X\in R^{n\times 2}$.

Now, finding the best fit reduces to $\hat B = (X^T X)^{-1}X^T Y$.

But I am interested in finding a $0.7$ confidence region around $\hat B$. How do I do that?

$\endgroup$

3 Answers 3

1
$\begingroup$

You could construct a Bayesian linear regression model to find the posterior $p(\theta\mid\mathcal{D})$ (where $\theta$ is the model parameters) and report the credible interval you're interested in, given the dataset $\mathcal{D} := \{ (x_i, y_i) \mid i = 1, 2, .., n \}$, where $x_i \in \mathbb{R}$ and $y_i \in \mathbb{R}^2$.

We will fit one regressor per target (aka two models given that our output is two dimensional)

Linear model forumlation

There are of course many options for choosing the underlying likelihood and priors of our model, but for clarity we will go for simple linear regression with both Gaussian likelihood and prior.

Likelihood: $$ p(y_{ij} \mid x_i ,\theta_j) = \mathcal{N}(\theta_{j_0} + \theta_{j_1}x_i, \sigma_j) $$

Priors:

$$ \theta_j \sim \mathcal{N}(\begin{bmatrix} 0 \\ 0 \end{bmatrix}, I) $$ $$ \sigma \sim \text{HalfNormal}(10) $$

Posterior: $$ p(\theta_j \mid \mathcal{D}) \propto \prod_{i=1}^{n}p(y_{ij} \mid x_i ,\theta_j) \ p(\theta_j)$$

which is the target of your analysis, knowing that you need to report the $0.7$ credible interval of $\theta_j$

If you're using Python, this blog post illustrates how to build Bayesian linear regression model using pymc3.

$\endgroup$
0
$\begingroup$

Looking at https://en.wikipedia.org/wiki/Simple_linear_regression :

This t-value has a Student's t-distribution with $n-2$ degrees of freedom. Using it we can construct a confidence interval for $\beta$:

$$ \beta \in \left[\widehat\beta - s_{\widehat\beta} t^*_{n - 2},\ \widehat\beta + s_{\widehat\beta} t^*_{n - 2}\right] $$

at confidence level $1-\gamma$, where $t^*_{n - 2}$ is the $(1-\frac{\gamma}{2})$-th quantile of the $t_{n−2}$ distribution.

$\endgroup$
1
  • $\begingroup$ So this would work if the regression I was doing was 1D, but I want to extend it to the case where the response variable is 2D $\endgroup$ Commented Jan 25, 2020 at 20:51
0
$\begingroup$

Bayesian linear regression can provide an estimate for the confidence region for a linear regression estimate.

$\endgroup$
2
  • $\begingroup$ Can you walk me through the math? What prior do I take? How do I update it efficiently? What is the resulting confidence region based on the posterior? $\endgroup$ Commented Mar 24, 2020 at 15:08
  • $\begingroup$ Isn't it "credible" region in Bayesian framework? $\endgroup$
    – Algo
    Commented May 11, 2022 at 5:25

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.